Answer:
We have to take 37.5 mL of a 0.400 M solution
Explanation:
Step 1: Data given
Stock volume = 100 mL = 0.100L
Stock concentration 0.400 M
Volume of solution he wants to make = 100 mL = 0.100L
Concentration of solution he wants to make = 0.150 M
Step 2: Calculate the volume of 0.400 M CuSO4 needed
C1*V1 = C2*V2
⇒with C1 = the stock concentration = 0.400M
⇒with V1 = the volume of the stock = TO BE DETERMINED
⇒with C2 = the concentration of the solution he wants to make = 0.150 M
⇒with V2 = the volume of the solution made = 0.100 L
0.400 M * V1 = 0.150M * 0.100L
V1 = (0.150M*0.100L) / 0.400 M
V1 = 0.0375 L = 37.5 mL
We have to take 37.5 mL of a 0.400 M solution
The volume of 0.400 M CuSO₄(aq) required for the preparation of the solution is 37.5 mL
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 0.4 M
Volume of diluted solution (V₂) = 100 mL
Molarity of diluted solution (M₂) = 0.15 M
M₁V₁ = M₂V₂
0.4 × V₁ = 0.15 × 100
0.4 × V₁ = 15
Divide both side by 0.4
V₁ = 15 / 0.4
Therefore, the volume of 0.400 M CuSO₄(aq) needed to prepare the solution is 37.5 mL
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