Answer:
c. 1/12
Step-by-step explanation:
im pretty sure this is the answer.
The theoretical probability of rolling a sum of 10 is 1/12.
Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.
For the given situation,
The sample space for rolling of two standard number cubes,
S = {
[tex](1,1),(1,2),(1,3),(1,4),(1,5),(1,6)\\ (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)\\(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)\\(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)[/tex] }
⇒ [tex]n(s)=36[/tex]
The event is that rolling a sum of 10.
[tex]e=[(4,6),(5,5),(6,4)][/tex]
[tex]n(e)=3[/tex]
Thus the theoretical probability of rolling a sum of 10 is
[tex]P(e)=\frac{n(e)}{n(s)}[/tex]
⇒ [tex]P(e)=\frac{3}{36}[/tex]
⇒ [tex]P(e)=\frac{1}{12}[/tex]
Hence we can conclude that the theoretical probability of rolling a sum of 10 is 1/12.
Learn more about probability here
https://brainly.com/question/23114605
#SPJ2
