Answer:
Heat change = 3.77kJ
Explanation:
T1 = 25°C
Mass = 65g
T2 = 30°C
specific heat capacity of water = 4.184J/g°C
Heat energy = ?
Heat energy = MC∇T
Heat energy (Q) = MC(T2 - T1)
Q = 65 * 4.184 * (30 - 15)
Q = 251.04 * 15
Q = 3765.6J
Q = 3.77KJ
The heat change during the reaction was 3.77kJ
