Answer:
[tex]\dfrac{7}{13}[/tex]
Step-by-step explanation:
Total Number of cards in a standard deck, n(S)=52
In a standard deck, there are 4 suits, 2 suits are black and 2 suits are red.
Number of Black Cards n(B)=26
Number of 4 cards, n(F)= 4
Number of Black cards with 4 on it, [tex]n(B\cap F)=2[/tex]
[tex]P(B\cup F)=P(B)+P(F)-P(B\cap F)\\=\dfrac{26}{52} +\dfrac{4}{52} -\dfrac{2}{52} \\=\dfrac{28}{52} \\\\P(B\cup F)=\dfrac{7}{13}[/tex]
Therefore, the probability that a card randomly selected from the container is a black card or 4 is 7/13.
