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A ball is thrown into the air. The function h(x) = −16(x − 2)2 + 72 models the height, in feet, of the ball after x seconds. What is the equation in standard form, and what is the maximum height of the ball?
A. h(x) = −16x2 + 32x + 72; 72 ft
B. h(x) = −16x2 − 32x + 72; 32 ft
C. h(x) = −16x2 − 64x + 32; 32 ft
D. h(x) = −16x2 + 64x + 8; 72 ft

Respuesta :

mysticchacha

Answer:

h(x) = -16 xx + 64 x + 8   , in Standard Form

Vertex at (2, 72)  maximum height at 72 feet

Step-by-step explanation:

We have: h(x) = −16(x − 2)2 + 72

this function is in Vertex form.

the Standard form is when we expand out the expression.

h(x) =  -16 *( x*x - 4x + 4)  + 72

h(x) = -16 xx + 64 x  - 64  + 72

h(x) = -16 xx + 64 x + 8

Vertex at (2, 72)  maximum height at 72 feet

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