Step-by-step explanation:
[tex]x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4(5) } }{2} \\ x = \frac{ - 5 + - \sqrt{25 - 20} }{2} \\ x = \frac{ - 5 + - \sqrt{5} }{2} [/tex]
Therefore, the zeroes would be:
[tex]x1 = \frac{ - 5 + \sqrt{5} }{2} \\ x2 = \frac{ - 5 - \sqrt{5} }{2} [/tex]
