Step-by-step explanation:
[tex]2(x+\frac{3}{4})^2-5=123[/tex]
1. Add 5 to both sides.
[tex]5+2(x+\frac{3}{4})^2-5=123+5[/tex]
[tex]2(x+\frac{3}{4})^2=128[/tex]
2. Divide both sides by 2.
[tex]\frac{2(x+\frac{3}{4})^2 }{2}=\frac{128}{2}[/tex]
[tex](x+\frac{3}{4} )^2=64[/tex]
3. Take the square root of both sides.
[tex]\sqrt[]{(x+\frac{3}{4})^2 } =\sqrt[]{64}[/tex]
[tex]x+\frac{3}{4}=8[/tex]
4. Subtract [tex]\frac{3}{4}[/tex] from both sides.
[tex]-\frac{3}{4}+x+\frac{3}{4}=8-\frac{3}{4}[/tex]
[tex]x=8-\frac{3}{4}[/tex]
[tex]x=\frac{(8)(4)-3}{4}[/tex]
[tex]x=\frac{32-3}{4}[/tex]
[tex]x=\frac{29}{4}[/tex]