Respuesta :
Direct Variation:
y = kx where k is the constant of variation
Number of essays: y
Number of hours: x
25 = k(4)
k = 25/4 ⇒ constant of variation
Find the number of hours (x) to grade 35 essays (y):
y = kx
35 = (25/4)(x)
x = (35)((4/25)
x = 140/25
x = 5 ³/₅ hours
(³/₅) (60 minutes) = 36 minutes
x = 5 hours and 36 minutes
Divide 25/4 to figure out how many essays the teacher grades in 1 hour.
It would take 5.36 hours.
y = kx where k is the constant of variation
Number of essays: y
Number of hours: x
25 = k(4)
k = 25/4 ⇒ constant of variation
Find the number of hours (x) to grade 35 essays (y):
y = kx
35 = (25/4)(x)
x = (35)((4/25)
x = 140/25
x = 5 ³/₅ hours
(³/₅) (60 minutes) = 36 minutes
x = 5 hours and 36 minutes
Divide 25/4 to figure out how many essays the teacher grades in 1 hour.
It would take 5.36 hours.
Answer:
9 tests per hour
Step-by-step explanation:
If it's quantities are directly, 27/3=9
The constant variation is 9.