Answer:
73 degrees
Step-by-step explanation:
From the given triangle
[tex]\angle EAB + \angle BAC=180^\circ(Linear\:Postulate)\\108^\circ+\angle BAC=180^\circ\\\angle BAC=180^\circ-108^\circ=72^\circ[/tex]
Similarly,
[tex]\angle FBC + \angle ABC=180^\circ(Linear\:Postulate)\\145^\circ+\angle ABC=180^\circ\\\angle ABC=180^\circ-145^\circ=35^\circ[/tex]
In Triangle ABC
[tex]\angle ABC + \angle BAC+\angle ACB =180^\circ(Sum\:of\:angles\:in\:a\:triangle)\\35^\circ+72^\circ+\angle ACB =180^\circ\\\angle ACB =180^\circ-35^\circ-72^\circ\\\angle ACB =73^\circ[/tex]
