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A box with a total surface area of 1.88 m^2
and
a wall thickness of 2.44 cm is made of an insulating material. A 14.1 W electric heater
inside the box maintains the inside temperature at 18.6
◦C above the outside temperature.
Find the thermal conductivity of the insulating material.
Answer in units of W/m ·
◦ C.

Respuesta :

Chelboy

Answer:9.8x10^(-3) w/m°C

Explanation:

Quantity of heat(Q)=14.1w

Distance(d)=2.44cm=2.44/100=0.0244m

Area(a)=1.88m^2

Temperature change(t)=18.6°C

thermal conductivity(k)=?

K=(Qxd) ➗ (a x t)

K=(14.1x0.0244) ➗ (1.88x18.6)

K=0.34404 ➗ 34.968

K=9.8x10^(-3) w/m°C

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