Answer:0.000665255mj
Explanation:
thermal conductivity(k)=0.41w/m°C
Area(a)=5.9x4=23.6m^2
Thickness(t)=16cm=16/100=0.16m
Change in temperature(T)=14-3=11°C
Quantity of heat=Q
Q=(kxaxT) ➗ t
Q=(0.41x23.6x11) ➗ 0.16
Q=106.436 ➗ 0.16
Q=665.255j=0.000665255mj