Answer:
Yes
Explanation:
The important rules for oxidation numbers are:
- The oxidation number of H in a compound is +1.
- The oxidation number of O in a compound is usually -2.
- The sum of the oxidation numbers in a compound is zero.
Thus, in your reaction, the oxidation numbers for S are:
[tex]\rm HBr + H_{2}\stackrel{\hbox{+6}}{\hbox{S}}O_{4} \longrightarrow \, \stackrel{\hbox{+4}}{\hbox{S}}O_{2} +Br_{2} + H_{2}O\\\text{The oxidation number of S $\large \boxed{\textbf{changes from +6 to +4}}$}[/tex]
