You're thinking b=1 will always give an integer, certainly true.
Then you think b=-1 will also always give an integer, so
Answer: ±1
Then you remember that a/b may not be a reduced fraction, so other bs beside the unit make give integers. The condition for an integer is
b | a
read 'b divides a' meaning a is a multiple of b.
Then you realize that a and b might not even b integers themselves.
Let's say the above answer is correct with the additional criteria that a and b are integers with no common factors.
Answer: b must equal a.
Or b must equal a multiple of the reciprocal of "a" if "a" is an integer.
Or "b" is a fraction with the numerator equal to "a" or a multiple of "a." If "a" is an integer
Step-by-step explanation:
Integers are whole numbers. If the denominator of the fraction is equal to the numerator, the value is 1 which is an integer.
If a is divided by its reciprocal the quotient is a whole number. For example: 3÷ 1/3 = 9. 4÷ 1/8= 32.
If b is a fraction that is not a multiple of the reciprocal, the quotient may be another non-intrger rational number. 3÷ 4/5 is 15/4 or 3 3/4.
7÷ 7/8 is 56/7 which is equivalent to 8, an integer.
