Respuesta :
Answer:
Step-by-step explanation:
Given the volume of the metal sheet = 1000m³
Surface area of the cylindrical tin can = 2πr(r+h)
r is the radius
h is the height of the can
Given diameter = 2r
r = d/2 = 3/2 = 1.5in
h = 4 1/4in = 17/4 in
On substituting
S = 2(3.14)(1.5)(1.5+4.25)
S = 9.42×5.75
S = 54.17in²
The total amount of cans they can make out of the sheet metal = Area of the sheet/surface area of the tin can
= 1000/54.17
= 18.46
Approximately 18 whole cans
b) yes, there will be left over sheet of metal
Left over = Area of the sheet metal - (Surface Area of can × total number of tin can formed)
= 1000-(18×54.17)
= 1000 - 975.06
= 24.94in² of metal sheet will be left over
Answer:
Number of whole cans with one sheet of metal: 18 cans
Leftover of metal: 24.535 in2
Step-by-step explanation:
First we need to find the surface area of one can.
The surface area is calculated by:
S = 2*pi*r^2 + 2*pi*r*h
Where r is the radius and h is the height.
Using r = 3/2 = 1.5 and h = 4 1/4 = 4.25 (the value in the image), we have that:
S = 2*pi*1.5^2 + 2*pi*1.5*4.25 = 54.1925 in2
If the sheet of metal has 1000 in2, to find how many whole cans can be made with one sheet, we just need to divide the area of the sheet by the surface area of the can:
Number of cans = 1000 / 54.1925 = 18.4527 -> 18 cans
The leftover of metal is 1000 - 54.1925*18 = 24.535 in2