hello,
[tex](3x + 5)^{2} = (3x + 5) \times (3x + 5) \\ \\ = 9 {x}^{2} + 15x + 15x + 25 \\ = {9x}^{2} + 30x + 25[/tex]
so,
a = 9, b = 30, c = 25.
[tex] \boxed {crsjr}[/tex]
The value of a + b + c is 64
To understand more, check below explanation.
We have to write given expression in [tex]ax^{2} +bx+c[/tex] format.
As we know that,
[tex](a+b)^{2} =a^{2} +b^{2} +2ab[/tex]
Given expression,
[tex](3x+5)^{2} =9x^{2} +25+30x\\\\(3x+5)^{2} =9x^{2} +30x+25[/tex]
After comparing, we get, a = 9, b = 30 and c = 25
So taht, a + b + c = 9+30+25 = 64
Learn more about the quadratic equation here:
https://brainly.com/question/1214333
