Answer:
Step-by-step explanation:
The choices to this question are
a.) 1/tan(90-A)
b.) 1/sin A
c.) 1/cos(90-A)
d.) 1/tan A
We know that
[tex]tanx=\frac{sinx}{cosx}[/tex], which is a trigonometric identity.
If [tex]tan(90-A)[/tex] then,
[tex]tan(90-A)=\frac{sin(90-A)}{cos(90-A)}[/tex]
But, [tex]sin (90-A)=cosA[/tex] and [tex]cos(90-A)=sinA[/tex]
So,
[tex]tan(90-A)=\frac{cosA}{sinA}[/tex]
Which is the inverse of tangent, so
[tex]tan(90-A)=\frac{1}{tanA}[/tex]
Therefore, the right answer is D.
