Answer:
[tex]m_{H_{2}} = 51.6\,g[/tex]
Explanation:
The mass ratio of hydrogen to nitrogen is:
[tex]r = \frac{6\cdot (1\,\frac{g}{mol} )}{2\cdot (14\,\frac{g}{mol} )}[/tex]
[tex]r = \frac{6}{28}[/tex]
[tex]r = \frac{3}{14}[/tex]
The required mass of hydrogen is:
[tex]m_{H_{2}} = \frac{3}{14}\cdot (17.2\,mol)\cdot (14\,\frac{g}{mol} )[/tex]
[tex]m_{H_{2}} = 51.6\,g[/tex]
