Answer: Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of [tex]20.0^0C[/tex] and a pressure of 15200 kPa
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 15200 kPa =150 atm (1kPa=0.0098atm)
V = Volume of gas = 47 L
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]20.0^0C=(20.0+273)K=293.0K[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{150atm\times 47L}{0.0821L atm/K mol\times 293.0K}=293moles[/tex]
Thus 293 moles of Oxygen gas can be stored in a standard gas cylinder at a temperature of [tex]20.0^0C[/tex] and a pressure of 15200 kPa
