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suppose that 16% of teenagers who play video gmes would enjoy playing a new super mario game the manufacturer doesnt know this actual proportion and plans on sampling a random sample of 80 teenage game players ap stats a. Calculate the standard deviation of the sampling distribution of p. b. Are the conditions for inference met?Explain c. If a different sample size would result in the standard deviation of the sample distripution of p= 0.037, is the sample size smaller or larger than 80?Explain

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sshyannrichardsstude

Answer:Accordingly, the Necessary Sample Size is calculated as follows:

Necessary Sample Size = (Z-score)² * StdDev*(1-StdDev) / (margin of error)²

For example, given a 95% confidence level, 0.5 standard deviation, and a margin of error (confidence interval) of +/- 5%. Necessary Sample Size =

((1.96)² x 0.5(0.5)) / (0.05)²

(3.8416 x 0.25) / .0025

0.9604 / 0.0025

384.16

So in order to get 95% confidence level, with confidence interval of +/- 5%, and standard deviation of 0.5, I have to survey 385 samples.

As I  usually calculate the average value on 100 samples. So what is the confidence level I can get?

Is anyone who has experience on this can share something.

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