Respuesta :
Answer:
[tex]\dfrac{2}{13}[/tex]
Step-by-step explanation:
Our sample space is the total number of cards in a deck, n(S)=52
Event A: Event that she chooses a three card
Number of 3 cards in a deck, n(A)=4
Event B: Event that she chooses a seven card.
Number of 7 cards in a deck, n(B)=4
In Probability, P(A or B)=P(A)+P(B)
[tex]P(A)=\dfrac{n(A)}{n(S)}= \dfrac{4}{52}= \dfrac{1}{13}\\P(B)=\dfrac{n(B)}{n(S)}= \dfrac{4}{52}= \dfrac{1}{13}\\P(A\: or \: B) = \dfrac{1}{13}+ \dfrac{1}{13}\\= \dfrac{2}{13}[/tex]
The probability that Zhi Qing chooses is either a three or a seven is 2/13.
