Respuesta :

Answer:

C. 2

Step-by-step explanation:

We have a circle described on the triangle. If one side of the triangle is the diameter of the circle, then the triangle is the right triangle.

Therefore m∠B = 90°.

AB is perpendicular to BC.

Let

k: y = m₁x + b₁ and l: y = m₂x + b₂

l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = - 1/m₁

We have the slope of BC m₁ = - 1/2.

Therefore the slope of AB m₂ = - 1/(- 1/2) = 2

took test on plato its right :)

The slope of AB is 2 units.

What is slope of line?

Slope of line is defined as the angle of line.  

ΔABC is a right triangle

So, AB is perpendicular to BC

If two lines are perpendicular, then the product of their slopes is equal to -1.

So, m₁m₂ = -1

mAB×mBC = -1

mAB = -1/mBC

[tex]mAB = \dfrac{-1}{-\frac{1}{2} }[/tex]

[tex]mAB = 2[/tex]

Hence, the slope of AB is 2 units.

Learn more about Slope of Line

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