Respuesta :
Answer:
C. 2
Step-by-step explanation:
We have a circle described on the triangle. If one side of the triangle is the diameter of the circle, then the triangle is the right triangle.
Therefore m∠B = 90°.
AB is perpendicular to BC.
Let
k: y = m₁x + b₁ and l: y = m₂x + b₂
l ⊥ k ⇔ m₁m₂ = -1 ⇒ m₂ = - 1/m₁
We have the slope of BC m₁ = - 1/2.
Therefore the slope of AB m₂ = - 1/(- 1/2) = 2
took test on plato its right :)
The slope of AB is 2 units.
What is slope of line?
Slope of line is defined as the angle of line.
ΔABC is a right triangle
So, AB is perpendicular to BC
If two lines are perpendicular, then the product of their slopes is equal to -1.
So, m₁m₂ = -1
mAB×mBC = -1
mAB = -1/mBC
[tex]mAB = \dfrac{-1}{-\frac{1}{2} }[/tex]
[tex]mAB = 2[/tex]
Hence, the slope of AB is 2 units.
Learn more about Slope of Line
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