What is the nuclear binding energy of an atom that has a mass defect of 5.0446 x 10-29 kg?
Use E = mc2. (Remember: The speed of light is approximately 3.00 x 108 m/s.)
5.61 x 10-46 J
O 1.51 x 10-20 J
O 4.54 x 10-12
O 1.78 x 1045 J

Respuesta :

Answer:

C: 4.54 x 10-12

Explanation:

On edg

4.54 × 10⁻¹² J is the nuclear binding energy of an atom that has a mass defect of 5.044 × 10⁻²⁹ kg.

Hence, Option (C) is correct answer.

What is Binding energy?

It is expressed as

ΔE = Δmc²

where

ΔE = Binding energy

ΔM = change in mass

c = speed of light

Now put the values in above formula we get

ΔE = Δmc²

     = (5.044 × 10⁻²⁹) × (3 × 10⁸ m/s)²

     = (5.044 × 10⁻²⁹) × (3 × 10⁸ m/s) × (3 × 10⁸ m/s)

     =  (5.044 × 10⁻²⁹) × (9 × 10¹⁶) (m/s)²

     = 45.4 × 10⁻¹³

     = 4.54 × 10⁻¹² J

Thus from the above conclusion we can say that 4.54 × 10⁻¹² J is the nuclear binding energy of an atom that has a mass defect of 5.044 × 10⁻²⁹ kg.

Hence, Option (C) is correct answer.

Learn more about the Binding energy here: brainly.com/question/23020604

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