Respuesta :
Answer:
The critical value is ±2.921.
Step-by-step explanation:
The (1 - α) % confidence interval for population mean for unknown population standard deviation (σ) is:
[tex]CI=\bar x\pm t_{\alpha/2, (n-1)}\ \frac{s}{\sqrt{n}}[/tex]
The information provided is:
n = 17
Confidence level = 99%
Compute the value of α as follows:
(1 - α) % = 99%
1 - α = 0.99
α = 0.01
The degrees of freedom of the t-value is:
degrees of freedom = n - 1
= 17 - 1
= 16
Compute the critical value of t as follows:
[tex]\text{Critical value}=t_{\alpha/2, (n-1)}[/tex]
[tex]=t_{0.01/2, 16}\\=t_{0.005, 16}\\=\pm 2.921[/tex]
*Use a t-table for the critical value.
Thus, the critical value is ±2.921.
Using the t-distribution, it is found that the appropriate critical value is t = 2.9208.
The standard deviation for the population is unknown, hence, the t-distribution is used.
To find the critical value, two parameters are needed.
- The confidence level.
- The number of degrees of freedom(df), which is one less than the sample size.
For this problem, there is a confidence level of 99% and 17 - 1 = 16 df, hence, using a t-distribution calculator, the critical value is t = 2.9208.
A similar problem is given at https://brainly.com/question/15180581