Explanation:
We have,
Radius of pizza, r = 18 m
Potential difference, V = 575 V
Stored electrical potential energy, E = 3.31 J
The area if an air-filled capacitor with parallel plates is equal to that of the pizza. It means, [tex]A=\pi r^2=\pi (18)^2=1017.87\ m^2[/tex]
The stored potential energy in a capacitor is given by :
[tex]E=\dfrac{1}{2}CV^2[/tex]
C is capacitance
[tex]C=\dfrac{2E}{V^2}\\\\C=\dfrac{2\times 3.31}{(575)^2}\\\\C=2\times 10^{-5}\ F[/tex]
The formula of the capacitance of a parallel plate capacitor is given by :
[tex]C=\dfrac{\epsilon_o A}{d}[/tex]
d is plate separation of this capacitor
[tex]d=\dfrac{\epsilon_o A}{C}\\\\d=\dfrac{8.85\times 10^{-12}\times 1017.87}{2\times 10^{-5}}\\\\d=4.5\times 10^{-4}\ m[/tex]
