Answer:
[tex]F_2=2000\ N[/tex]
Explanation:
We have,
Area 1, [tex]A_1=1\ m^3[/tex]
Force 1, [tex]F_1=100\ N[/tex]
Area 2, [tex]A_2=20\ m^3[/tex]
It is required to find the force 2. In a hydraulic lift, the pressure at two points is same. It means :
[tex]P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}[/tex]
[tex]F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{100\times 20}{1}\\\\F_2=2000\ N[/tex]
So, second force is 2000 N.
