Answer:
The percentage/protocol overheads is about 7.8125 %
Explanation:
Solution
Recall that the TCP header contains a 20 bytes and IP header also contains 20 bytes.
The total of the overhead now is 40 bytes
Now,
let 2048 bytes be divided by 4 segments
Thus, it becomes (40+512) *4 = 2208
Therefore 2208 byes are sent by only 4 segments.
Now what is the overhead protocol
(1) Since 2048 = 100%
let 2208 be = X%
Then,
X=2208 * 100/2048 = 107.8125, that is from 100 % increased the 7.8125
therefore. the percentage overheads is about 7.8125 %