Respuesta :
Area of pool = 2 x area of sector + 2 x area of triangle
Area of sector = [tex] \frac{ \theta}{2 \pi } \times \pi r^2=\frac{ 2.21}{2} \times 30^2 =1.105 \times 900=994.5 \ square \ feet[/tex]
Area of triangle = 1/2 bh = 1/2 x 20 x 25 = 250 square feet
Area of pool = 2(994.5) + 2(250) = 1,989 + 500 = 2,489 square feet = 2,490 square feet.
Area of sector = [tex] \frac{ \theta}{2 \pi } \times \pi r^2=\frac{ 2.21}{2} \times 30^2 =1.105 \times 900=994.5 \ square \ feet[/tex]
Area of triangle = 1/2 bh = 1/2 x 20 x 25 = 250 square feet
Area of pool = 2(994.5) + 2(250) = 1,989 + 500 = 2,489 square feet = 2,490 square feet.