"Vector A⃗ , which is shown in the figure, has a magnitude of 10 and a direction angle of 60º. What is the magnitude and direction angle (as measured counterclockwise from the positive x-axis) of −A⃗ /2?



-5, 60º
5, 240º
5, -30º
-5, -30º
-5, 240º"

Vector A which is shown in the figure has a magnitude of 10 and a direction angle of 60º What is the magnitude and direction angle as measured counterclockwise class=

Respuesta :

Answer: Second option 5, 240°

Magnitude of vector A=10
Direction angle of vector A=60°

-A/2 is a vector with magnitude equal to the half of the magnitude of the vector A and direction opposite to the direction of vector A, because the minus sign, then:

Magnitude of vector -A/2=Magnitude of vector A / 2 =10/2→
Magnitude of vector -A/2=5

Direction angle of vector -A/2=Direction angle of vector A + 180°=60°+180°→
Direction angle of vector -A/2=240°

Answer: Second option 5, 240°

The magnitude and direction angles ( as measured counterclockwise from the positive x - axis ) of - A / 2 is 5 and 240º

Further explanation

Vector is quantity that has magnitude and direction.

One example of a vector is acceleration.

Let us now tackle the problem !

This problem is about Vector Diagram.

Given:

Vector A = (10 cos 60°) i + (10 sin 60°) j = 5 i + 5√3 j

Unknown:

Vector A/2 = ?

Solution:

[tex]\overrightarrow{A} = 5~\widehat{i} + 5\sqrt{3}~\widehat{j}[/tex]

[tex]-\overrightarrow{A} / 2 = -(5~\widehat{i} + 5\sqrt{3}~\widehat{j}) \div 2[/tex]

[tex]-\overrightarrow{A} / 2 = -\frac{5}{2} ~\widehat{i} - \frac{5}{2}\sqrt{3}~\widehat{j}[/tex]

[tex]|-\overrightarrow{A} / 2| = \sqrt{(-\frac{5}{2})^2 + (- \frac{5}{2}\sqrt{3})^2}[/tex]

[tex]|-\overrightarrow{A} / 2| = \sqrt{25}[/tex]

[tex]|-\overrightarrow{A} / 2| = 5[/tex]

[tex]\tan \theta = (- \frac{5}{2}\sqrt{3}) \div (-\frac{5}{2})[/tex]

[tex]\tan \theta = \sqrt{3}[/tex]

[tex]\theta = 180^o + 60^o[/tex]

[tex]\theta = 240^o[/tex]

From the results above, it can be concluded that the magnitude and direction angles ( as measured counterclockwise from the positive x - axis ) of - A / 2 is 5 and 240º

Learn more

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Answer details

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate, Stream , Vector

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