Respuesta :
Answer: Second option 5, 240°
Magnitude of vector A=10
Direction angle of vector A=60°
-A/2 is a vector with magnitude equal to the half of the magnitude of the vector A and direction opposite to the direction of vector A, because the minus sign, then:
Magnitude of vector -A/2=Magnitude of vector A / 2 =10/2→
Magnitude of vector -A/2=5
Direction angle of vector -A/2=Direction angle of vector A + 180°=60°+180°→
Direction angle of vector -A/2=240°
Answer: Second option 5, 240°
Magnitude of vector A=10
Direction angle of vector A=60°
-A/2 is a vector with magnitude equal to the half of the magnitude of the vector A and direction opposite to the direction of vector A, because the minus sign, then:
Magnitude of vector -A/2=Magnitude of vector A / 2 =10/2→
Magnitude of vector -A/2=5
Direction angle of vector -A/2=Direction angle of vector A + 180°=60°+180°→
Direction angle of vector -A/2=240°
Answer: Second option 5, 240°
The magnitude and direction angles ( as measured counterclockwise from the positive x - axis ) of - A / 2 is 5 and 240º
Further explanation
Vector is quantity that has magnitude and direction.
One example of a vector is acceleration.
Let us now tackle the problem !
This problem is about Vector Diagram.
Given:
Vector A = (10 cos 60°) i + (10 sin 60°) j = 5 i + 5√3 j
Unknown:
Vector A/2 = ?
Solution:
[tex]\overrightarrow{A} = 5~\widehat{i} + 5\sqrt{3}~\widehat{j}[/tex]
[tex]-\overrightarrow{A} / 2 = -(5~\widehat{i} + 5\sqrt{3}~\widehat{j}) \div 2[/tex]
[tex]-\overrightarrow{A} / 2 = -\frac{5}{2} ~\widehat{i} - \frac{5}{2}\sqrt{3}~\widehat{j}[/tex]
[tex]|-\overrightarrow{A} / 2| = \sqrt{(-\frac{5}{2})^2 + (- \frac{5}{2}\sqrt{3})^2}[/tex]
[tex]|-\overrightarrow{A} / 2| = \sqrt{25}[/tex]
[tex]|-\overrightarrow{A} / 2| = 5[/tex]
[tex]\tan \theta = (- \frac{5}{2}\sqrt{3}) \div (-\frac{5}{2})[/tex]
[tex]\tan \theta = \sqrt{3}[/tex]
[tex]\theta = 180^o + 60^o[/tex]
[tex]\theta = 240^o[/tex]
From the results above, it can be concluded that the magnitude and direction angles ( as measured counterclockwise from the positive x - axis ) of - A / 2 is 5 and 240º
Learn more
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Answer details
Grade: High School
Subject: Mathematics
Chapter: Vectors
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate, Stream , Vector