Hey there, Lets solve this problem together.
You are given two lengths of a right angled triangle, so Pythagoras' theorem is the way to go.
In algebraic terms, a² + b² = c² where c is the hypotenuse while a and b
are the legs of the triangle.
In a right angled triangle:
the square of the hypotenuse is equal to
the sum of the squares of the other two sides.
c² (the diagonal squared) = a² (one length squared) + b²
(the other length squared)
leg a and b are both 3
[tex]3^2 + 3^2 = c^2
[/tex]
[tex]= 3 * 3 = 3^2
[/tex]
[tex]= 9 + 9 = c^2[/tex]
[tex]9 + 9 =18 [/tex]
[tex]18 = c^2[/tex]
The opposite of ^2 is ^1/2 also known as the square root
c = sqrt(18)Solved =
c≈4.24
