At a store, apples cost $0.80 $0.80 each and oranges cost $0.95 $0.95 each. Harry buys some apples and oranges and spends $9.55 $9.55 . He buys a total of 11 11 pieces of fruit.

Total money spend is equal to number of apples bought multiplied by Cost of each apples plus number of oranges were bought multiplied by Cost of each oranges.

framing in equation form we get;

[tex]0.8a+0.95o=9.55[/tex] ⇒ equation 2

Now Multiplying equation 1 by 0.8 we get;

[tex]0.8(a+o)=0.8\times11[/tex]

[tex]0.8a+0.8o=8.8[/tex] ⇒ equation 3

Subtracting equation 3 from equation 2 we get;

[tex]0.8a+0.95o-(0.8a+0.8o)=9.55-8.8\\\\0.8a+0.95o-0.8a-0.8o=0.75\\\\0.15o=0.75[/tex]

Dividing both side by 0.15 we get;

[tex]\frac{0.15o}{0.15}=\frac{0.75}{0.15}\\\\o=5[/tex]

Substituting the value of o in equation 1 we get;

[tex]a+o=11\\\\a+5=11\\\\a=11-5=6[/tex]

Hence Harry buys 6 apples and 5 oranges at the store.

facundo3141592 facundo3141592 · Answer 2 · 2022-03-29T13:51:41+02:00

By solving a system of equations, we will see that he bought 6 apples and 5 oranges.

How many of each fruit did Harry buy?

Let's define the variables:

x = number of oranges bought.
y = number of apples bought.

We know that he buys a total of 11 pieces of fruit, so we have:

x + y = 11

We also know that he spends in total $9.55, then:

x*$0.95 + y*$0.80 = $9.55

Then we have a system of equations:

x + y = 11

x*$0.95 + y*$0.80 = $9.55

To solve this system, first, we need to isolate one of the variables in one of the equations, we can do it in the first one.

x = 11 - y

Replacing that in the other equation we get:

(11 - y)*$0.95 + y*$0.80 = $9.55

Now we can solve this for y:

11*$0.95 - y*$0.15 = $9.55

-y*$0.15 = $9.55 - $10.45 = -$0.90

y = $0.90/$0.15 = 6

So he bought 6 apples, and the other 5 pieces of fruit are oranges.

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904