Answer:
The answer to your question is V2 = 0.58 l
Explanation:
Data
Pressure 1 = P1 = 110 kPa Pressure 2 = P2 = 440 kPa
Temperature 1 = T1 = 30°C Temperature 2 = T2 = 80°C
Volume 1 = V1 = 2 L Volume 2 = V2 = ?
Process
- Use the combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution (temperature must be in °K)
V2 = (110 x 2 x (80 + 273)) / (30 + 273)(440)
-Simplification
V2 = (220 x 353) / (303 x 440)
V2 = 77660 / 133320
-Result
V2 = 0.58 l
