Answer:
The answer is 200
Step-by-step explanation:
To solve the question given, let us recall the following,
Let r4=200 miles apart
r=50 mph combined speed
Where
2f+10=50
2f=40
f=20
f+10=30
or we can express it in another way,
which is
f x4+(f+10)x 4=200
f x4+f x4+40=200
8f+40=200
Then
8f is =160
f=20
f+10=30
Therefore,
4x 20+4 x 30=200
80+120=200
200=200
Answer:
First vagabond: 30 miles per hour
Second vagabond: 20 miles per hour
Step-by-step explanation:
Let's call the speed of the first vagabond A, and the speed of the second vagabond B.
They were heading toward each other, so the relative speed is the sum of both speeds: A+B
The total number of hours spent until they meet is 6 - 2 = 4 hours, so we have the first equation:
(A+B) * 4 = 200
A + B = 50
One vagabond was traveling 10 miles faster than the other, so we have the second equation:
A = B + 10
Using the value of A from the second equation in the first one, we have:
B + 10 + B = 50
2B = 40
B = 20 miles per hour
Now, from the second equation, we find the value of A:
A = 20 + 10 = 30 miles per hour
