Answer:
Step-by-step explanation:
length = x m
Width = (x - 6) m
Area = 135 sq.m
length * width = 135
x*(x-6) = 135
x*x - x*6 -135 = 0
x²- 6x - 135 = 0
x² - 15x + 9x - 9*15 = 0
x(x - 15) + 9(x-15) = 0
(x-15)(x + 9) = 0
x - 15 = 0
{x+9=0 is ignored because measurement cannot be a negative number}
x= 15
length = 15 m
width = x - 6 = 15 - 6 = 9 m
Perimeter = 2*(length + width)
= 2*(15 + 9) = 2 * 24 = 48 m
Answer:
The perimeter of the rectangle is 48 m.
Step-by-step explanation:
Given:
Area of rectangle=153 sq.m
and
width=b and length=l
b=(l-6) m
To find :
Perimeter of given rectangle
Solution:
we know that the
area of rectangle is given by,
[tex]l*b=135[/tex]
[tex]l(l-6)=135[/tex]
[tex]l^2-6l-135[/tex]=0
solve this quadratic equation,
we get ,
[tex](l+9)(l-15)[/tex]
length will not be negative
therefore l=15 m
hence,[tex]b=l-6[/tex]
[tex]b=15-6[/tex]
b= 9 m
Now perimeter is
[tex]2(l+b)[/tex]
=[tex]2(15+9)[/tex]
=48 m
