The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random variable ranging from 2 to 7. Find the mean and standard deviation of this random variable. (Round your answers to 2 decimal places.) Mean Standard deviation

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Answer:

The mean is 4.5 and the standard deviation is 1.44.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

[tex]M = \frac{(a + b)}{2}[/tex]

The standard deviation of the uniform probability distribution is:

[tex]S = \sqrt{\frac{(b-a)^{2}}{12}}[/tex]

Uniformly distributed random variable ranging from 2 to 7.

This means that [tex]a = 2, b = 7[/tex].

So

[tex]M = \frac{(2 + 7)}{2} = 4.5[/tex]

[tex]S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(7 - 2)^{2}}{12}} = 1.44[/tex]

The mean is 4.5 and the standard deviation is 1.44.