Respuesta :
Answer:
[tex]L(t)=7600(5)^{t/2}[/tex]
Explanation:
Amend the typos for better understanding:
- On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom. The locust population increases by a factor of 5 every 2 days, and can be modeled by a function, L, which depends on the amount of time, t (in days). Before the first day of spring, there were 7600 locusts in the population. Write a function that models the locust population t days since the first day of spring.
Solution
A function that grows with a constant factor is modeled by an exponential function of the kind:
[tex]F(x)=A\cdot (B)^x[/tex]
Where A is the initial value, B is the constant growing factor, and x is the number of times the growing factor applies.
Since the population increases by a factor of 5 every 2 days, the power x of the exponential function is t/2, and the factor B is 5.
The initial popultaion A is 7600.
Thus, the function that models the locust population t days since the first day of spring is:
[tex]L(t)=7600(5)^{t/2}[/tex]