Step-by-step explanation:
RAGL is a rhombus.
[tex] \therefore RA = AG..
(sides\: of\: rhombus) \\
\therefore m\angle ARG = m\angle AGR... (1)[/tex]
(Angles opposite to equal sides are equal)
[tex] In\:\triangle RAG, \\
m\angle ARG +\bold{ m\angle AGR} + {m\angle RAG} = 180°\\
m\angle ARG +\bold {m\angle ARG} + 58° = 180°\\
[From\:equation \: (1)]\\
2m\angle ARG = 180°-58° \\
2m\angle ARG = 122° \\
m\angle ARG =\frac{122°}{2} \\
\huge \red {\boxed {m\angle ARG = 61°}} [/tex]
Hence, option A is the correct answer.
