Given:
Height of cylinder = 6 inches
Volume of cylinder = 60π in³
To find:
The area of the cross section.
Solution:
Volume of cylinder:
[tex]V=\pi r^2h[/tex]
[tex]\pi r^2h=60\pi[/tex]
Cancel the common factor π on both sides.
[tex]r^2h=60[/tex]
Substitute h = 6.
[tex]r^2\times 6=60[/tex]
Divide by 6 on both sides, we get
[tex]r^2=10[/tex]
Taking square root on both sides.
[tex]r=\sqrt{10}[/tex] inch
Area of cross section = [tex]\pi r^2[/tex]
[tex]=\pi (\sqrt{10} )^2[/tex]
[tex]=10 \pi[/tex] in²
The area of the cross section is 10π in².
