Answer:
theoretical fracture strength = 16919.98 MPa
Explanation:
given data
Length (L) = 0.28 mm = 0.28 × 10⁻³ m
radius of curvature (r) = 0.002 mm = 0.002 × 10⁻³ m
Stress (s₀) = 1430 MPa = 1430 × 10⁶ Pa
solution
we get here theoretical fracture strength s that is express as
theoretical fracture strength = [tex]s_{0} \times \sqrt{\frac{L}{r} }[/tex] .............................1
put here value and we get
theoretical fracture strength = [tex]1430 \times 10^6\times \sqrt{\frac{0.28\times 10^{-3}}{0.002\times 10^{-3}} }[/tex]
theoretical fracture strength = [tex]16919.98 \times 10^6[/tex]
theoretical fracture strength = 16919.98 MPa
