Answer:
(4 × 10⁻⁵) N
Explanation:
Magnetic force between two current carrying wires is given as
(F/L) = (μ₀I₁I₂)/2πr
where (F/L) = Force per unit length
L = Length of the wire section = 1 m
μ₀ = magnetic constant = (4π × 10⁻⁷) H/m
I₁ = Current in wire 1 = 1.00 A
I₂ = Current in wire 2 = 1.00 A
r = distance between the wires = 5.00 mm = 0.005 m
(F/L) = (μ₀I₁I₂)/2πr
(F/L) = [(4π × 10⁻⁷ × 1 × 1)/(2π × 0.005)]
(F/L) = 0.00004 N/m
F = 0.00004 × 1 = 0.00004 N = (4 × 10⁻⁵) N
Hope this Helps!!!
