Answer:
Explanation:
Given:
Number of turns [tex]N = 200[/tex]
Cross sectional area [tex]A = 10^{-3}[/tex] [tex]m^{2}[/tex]
Rate of increasing magnetic field [tex]\frac{dB}{dt} = 6[/tex] [tex]\frac{T}{s}[/tex]
From the faraday's law,
Induced emf is given by,
[tex]\epsilon = -N\frac{d \phi}{dt }[/tex]
Where [tex]\phi =[/tex] magnetic flux
[tex]\phi = AdB \cos(0)[/tex] ( because angle between normal coil and field is zero)
Where [tex]A =[/tex] area of coil
Put the value of [tex]\phi[/tex] in above equation,
Here we neglect minus sign
[tex]\epsilon = NA\frac{dB}{dt}[/tex]
[tex]\epsilon = 200 \times 10^{-3} \times 6[/tex]
[tex]\epsilon = 1.2[/tex] V
Therefore, 1.2 volt induced in coil
