Respuesta :
Answer:
first ball is at rest after collision and the kinetic energy of the first ball is transferred to the second ball after collision.
Explanation:
mass of each ball = m
initial velocity of first ball = u
initial velocity of second ball = 0 m/s
final velocity of second ball = initial velocity of first ball = u
Use conservation of momentum
let v is the final velocity of the first ball after collision
m x u + m x 0 = m x v + m x u
So, v = 0
It means after the collision the second ball moves with the velocity which is equal to the initial velocity of the first ball and the first ball comes at rest.
As there is no friction between the balls during the collision, the collision of two balls is perfectly elastic and thus the kinetic energy of the system is conserved.
The entire kinetic energy of the first ball is transferred to the second ball after the collision.
The entire kinetic energy of ball 1 will be totally transferred to the second ball after the collision.
According to the law of conservation of momentum, the change in momentum of a body before the collision is equal to the change in momentum after the collision.
The formula for calculating momentum is expressed as:
[tex]\rho = mv \\[/tex]
According to the conservation of momentum
[tex]m_1u_1+m_2u_2=(m_1+m_2)v[/tex]
Since ball 2 is initially at rest [tex]u_2=0[/tex]
Also if after the collision, ball 2 departs with the same velocity that ball 1 originally had, hence [tex]v=u_1[/tex]
Substituting the given parameters into the formula:
[tex]m_1u_1+m_2(0)=(m_1+m_2)u_1\\m_1u_1=m_1u_1+m_2u_2\\m_2u_2=0[/tex]
This shows that the velocity of the second ball is also zero
Due to the absence of friction between the colliding object, the collision is elastic in nature showing that the kinetic energy of the system is conserved.
The entire kinetic energy of ball 1 will be totally transferred to the second ball after the collision.
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