Answer:
[tex]18.8\times 10^{-3} T[/tex]
Explanation:
We are given that
Number of turns,N=500
Radius,r=0.04 m
Length of solenoid,L=40 cm=[tex]\frac{40}{100}=0.4 m[/tex]
1 m=100 cm
Current,I=12 A
We have to find the magnitude of magnetic field near the center of the solenoid.
Number of turns per unit length,n=[tex]\frac{500}{0.4}=1250[/tex]
Magnetic field near the center of the solenoid,B=[tex]\mu_0 nI[/tex]
Where [tex]\mu_=0=4\pi\times 10^{-7}Tm/A[/tex]
[tex]B=4\pi\times 10^{-7}\times 1250\times 12=18.8\times 10^{-3} T[/tex]
[tex]B=18.8\times 10^{-3} T[/tex]
