Respuesta :
Answer:
We have,
max 4x+10y
3x+4y<480
4x+2y<360
The feasible corner points are ( 48,84),(0,120),(0,0),(90,0)
Now, our problem is maximum type so put above feasible points in equation max 4x + 10y one by one and select one point at which our value from this equation is maximum,
(48,84) 4*48+10*84 1032
(0,120) 4*0+10*120 1200
(0,0) 4*0+10*0 0
(90,0) 4*90+10*0 360
Here we get maximum value at (0,120) which is 1200.
Correct option is (B)1200
Answer:
Answer is 1200.
Refer below.
Step-by-step explanation:
The maximum possible value for the objective function is 1200.
