Respuesta :
Answer:
t = 0.325343 sec
Explanation:
given
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
we know simple harmonic motion equation as
y = A sin (ωt + Φ)
where Φ = [tex]sin^{-1} (-4/6)[/tex]
so we get
Φ = - 0.729727656 rad
and we know
[tex]\omega = \sqrt{\frac{k}{m}[/tex]
[tex]y = A sin (t\sqrt\frac{k}{m} - 0.729727656)[/tex]
now substitute the values we get as
y = 0.06 m
[tex]0.06 = 0.06 sin (t\sqrt(\frac{25}{0.5}) - 0.729727656)[/tex]
[tex](t\frac{25}{0.5} - 0.729727656) = \frac{\pi}{2}[/tex]
on solving these equation we get
t = 0.325343 sec
The time where t1 will it first reach the limit of its motion to the right is 0.325343 sec.
Calculation of the time taken:
Since
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
Here we apply the harmonic motion equation i.e.
y = A sin (ωt + Φ)
where Φ = sin^-(-4/6)
Φ = - 0.729727656 rad
Now
w = √k/m
y = Asin (t√k/m - 0.729727656)
y = 0.06m
Now
(t2.5/0.5 - 0.729727656) = π/2
t = 0.325343 sec
Hence, The time where t1 will it first reach the limit of its motion to the right is 0.325343 sec.
Learn more about motion here; https://brainly.com/question/26962882?referrer=searchResults
