54.03 moles of gas were left the next morning, assuming the temperature and volume of the tank stayed constant.
Explanation:
Status of the oxygen gas at night or initial conditions.
volume of the tank = 70 litre
temperature = 27 degree celsius or 300.15 K
pressure = ?
number of moles of oxygen = 119
R = 0.0821 L atm/mole K
applying gas law
PV = nRT
P = [tex]\frac{0.0821 X 119.4 X 300.15}{70}[/tex]
P = 42 atm
in the morning
volume = 70 litres
temperature = 300.15 K
Pressure = 19 atm
n = ?
R = 0.0821 L atm/mole K
Applying Ideal Gas law,
PV= nRT
putting the values in the formula:
n = [tex]\frac{19 X 70}{0.0821 X 300.15}[/tex]
n = 54.03 moles will be left in the morning.
