Answer:
Absolute pressure=density*g*h
Absolute pressure=1000*9.8*1.9
Absolute pressure=18260 N/m^2
Force on the bottom=PA=18260*(30)(8.9)=4971540 N
Answer:
A)P = 1.2 × 10⁵Pa
B)F = 3.2 × 10⁷N
C) P = 1.2 × 10⁵Pa
Explanation:
Part A)
The relative pressure at the bottom of a column of fluid is given by
[tex]p_r = \rho g h[/tex]
where
[tex]\rho[/tex] is the fluid density
g is the gravitational acceleration
h is the height of the column of fluid
At the bottom of the swimming pool, h=1.9 m, and the water density is
[tex]\rho[/tex] = 1000 kg/m^3, therefore the relative pressure is
[tex]p_r = (1000 kg/m^3)(9.81 m/s^2)(1.9 m)=1.86 \cdot 10^4 Pa[/tex]
To find the absolute pressure, we must add to this the atmospheric pressure, [tex]p_a[/tex] :
[tex]p= p_r + p_a\\= 1.86 \cdot 10^4 Pa + 1.01 \cdot 10^5 Pa \\=1.2 \times 10^5 Pa[/tex]
part B
Total force acting on the bottom
force = pressure * area
area of pool = 30.0 m × 8.9 m
= 267m²
Force F =
1.2 × 10⁵ * 267m² N
= 32040000 N
F = 3.2 × 10⁷N
Part C
The pressure acting on the side wall will be
now the pressure at the side of the pool at the bottom is simply equal to absolute pressure as they are at same level
P = 1.2 × 10⁵
