Answer:
Net forces which pushes the window is 30342.78 N.
Explanation:
Given:
Dimension of the office window.
Length of the window = [tex]3.1[/tex] m
Width of the window = [tex]2.1[/tex] m
Area of the window = [tex](3.1\times 2.1) = 6.51\ m^2[/tex]
Difference in air pressure = Inside pressure - Outside pressure
= [tex](1.0-0.954)[/tex] atm = [tex]0.046[/tex] atm
Conversion of the pressure in its SI unit.
⇒ [tex]1[/tex] atm = [tex]101325[/tex] Pa
⇒ [tex]0.046[/tex] atm = [tex]0.046\times 101325 =4660.95[/tex] Pa
We have to find the net force.
We know,
⇒ Pressure = Force/Area
⇒ [tex]Pressure=\frac{Force }{Area}[/tex]
⇒ [tex]Force =Pressure\times Area[/tex]
⇒ Plugging the values.
⇒ [tex]Force =4660.95\times 6.51[/tex]
⇒ [tex]Force=30342.78[/tex] Newton (N)
So,
The net forces which pushes the window is 30342.78 N.
