Respuesta :
Answer:
86.48 dB . Ans
Explanation:
Sound level by one singer = 70.8 dB
= 7.08 B
If I be its intensity in terms of watt/m²
log ( I / 10⁻¹² ) = 7.08 ( given )
I / 10⁻¹² = 10⁷°⁰⁸
I = 10⁻¹² x 10⁷°⁰⁸
= 10⁻⁴°⁹²
= .000012022 W / m²
intensity by 37 singers
= 37 x .000012022 W /m²
= .0004448378
= 4448.378 x 10⁻⁷
intensity level
= log I / 10⁻¹² B
= log 4448.378 x 10⁻⁷ / 10⁻¹²
= log 444837800 B
log 4448378 + 2 B
= 6.6482 +2 B
8.6482 B
intensity level = 8.6482 B
= 86.48 dB . Ans
Answer:
86.48 dB
Explanation:
86.48 dB
Explanation:
sound level intensity, β = 70.8 dB
Io = 10^-12 W/m²
Let the intensity if I at the level of 70.8 dB
Use the formula
7.08 = log I + 12
log I = - 4.92
I = 1.2 x 10^-5 W/m²
There are 37 singers, so the total intensity is I'.
I' = 37 x I
I' = 37 x 1.2 x 10^-5 = 4.45 x 10^-4 W/m²
Let the sound intensity is β' in decibels.
Use the formula
β' = 86.48 dB
