Respuesta :
Answer: 10.67 m/s²
Explanation:
Given, l = 50 cm = 0.5 m
T = 2π √(L / g) , where
L = length of spring
g = acceleration due to gravity
T = period
T can also be gotten using the formula,
T = total number of oscillations / time taken, so that
T = 136 / 100
T = 1.36
T = 2π √(L / g)
1.36 = 2 * π * √(0.5 / g)
1.36 = 6.284 * √(0.5 / g)
1.36² = 6.284² * (0.5 / g)
1.85 = 39.49 * 0.5 / g
g = 19.745 / 1.85
g = 10.67 m/s²
Thus, we can infer that the value of g on this planet is 10.67 m/s²
Answer:
g = 10.67 m/s²
Explanation:
The period of a simple pendulum is given as;
T = 2π√(L / g)
Where;
T = period
L = length of spring
g = acceleration due to gravity
Now, in the question we want to find g and we are given L but not given the period.
We are given
So let's find the period (T)
We are given total number of oscillations and time taken to complete those oscillations. Thus, we can express period as;
T = time taken/total number of oscillations
So, T = 136/100 = 1.36
Thus,
1.36 = 2π√(L / g)
1.36/2π = √(L / g)
Taking the square of both sides, we have;
(1.36/2π)² = L/g
0.04685 = L/g
We are given that; L = 50cm = 0.5m
So,
0.04685 = 0.5/g
g = 0.5/0.04685
g = 10.67 m/s²
