contestada

A ball is thrown vertically upward. After seconds, its height (in feet) is given by the function 56t - 16t^2 . What is the maximum height that the ball will reach?

Respuesta :

Answer:

Therefore the maximum height that the reach is 49 feet after 1.75 seconds.

Step-by-step explanation:

Given that,

A ball is thrown vertically upward. After t seconds its height is given by the function

[tex]h=56t-16 t^2[/tex]

where h is height in feet.

Maximum value:

Given function f(x)= at²+bt+c.

  1. Find the value [tex]-\frac{b}{2a}[/tex]
  2. Putting [tex]x= -\frac{b}{2a}[/tex] in the given function.
  3. The maximum value of the given function is [tex]f(-\frac{b}{2a})[/tex].

Here a= -16 ,  b=56 and c=0

The ball attains its maximum height when [tex]t=-\frac{56}{2.(-16)}=1.75[/tex] s.

Putting the value of t in the given function

[tex]h=(56\times 1.75)-16(1.75)^2[/tex]

  =49 feet

Therefore the maximum height that the reach is 49 feet after 1.75 seconds.

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